【解題】Zerojudge d732: 二分搜尋法

題目連結

d732: 二分搜尋法

我的想法

純純的二分搜尋

範例:找 8

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2
3
1 2 3 4 5 6 7 8 9
↑ ↑ ↑
l m r

5 < 8 所以左邊往中點 +1 移動

1
2
3
1 2 3 4 5 6 7 8 9
↑ ↑ ↑
l m r

7 < 8 所以左邊往中點 +1 移動

1
2
3
4
1 2 3 4 5 6 7 8 9
↑ ↑
l r
(m)

8 = 8 所以結束二分搜

參考解答

d732
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#include <iostream>
using namespace std;

void solve(int *data, int n, int qq) {
int left = 0;
int right = n;
while (left <= right) {
int mid = (left + right) / 2;
if (data[mid] < qq) {
left = mid + 1;
} else if (data[mid] > qq) {
right = mid - 1;
} else {
cout << mid + 1 << "\n";
return;
}
}
cout << 0 << "\n";
return;
}

int main() {
int n, k;
cin >> n >> k;
int data[n], q[k];
for (int i = 0; i < n; i++) {
cin >> data[i];
}
for (int i = 0; i < k; i++) {
cin >> q[i];
}
for (int i = 0; i < k; i++) {
solve(data, n, q[i]);
}
return 0;
}